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x^2-89=7x
We move all terms to the left:
x^2-89-(7x)=0
a = 1; b = -7; c = -89;
Δ = b2-4ac
Δ = -72-4·1·(-89)
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9\sqrt{5}}{2*1}=\frac{7-9\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9\sqrt{5}}{2*1}=\frac{7+9\sqrt{5}}{2} $
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